2x^2+75x-3125=0

Solution for 2x^2+75x-3125=0 equation:

2x^2+75x-3125=0

a = 2; b = 75; c = -3125;
Δ = b2-4ac
Δ = 752-4·2·(-3125)
Δ = 30625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{30625}=175$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-175}{2*2}=\frac{-250}{4}
=-62+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+175}{2*2}=\frac{100}{4}
=25
$